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Question
primary 5 | Maths
| Rate & Ratio
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Mkk
Date Posted: 3 years ago
Views: 381
Just subtract the area of the smaller triangle from the bigger one.
The two unshaded areas will cancel out. leaving you with the difference in shaded areas
The two unshaded areas will cancel out. leaving you with the difference in shaded areas
½ ×9×(16-10) = 27cm² (Ans)
【diff unchanged】
【diff unchanged】
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done
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There. Hope it helps
Date Posted:
3 years ago
Thank you . Just don't understand why x9 because not when it is not full length
9cm is the length of the base, not the whole stretch from one arrow to the other
Area of any triangle is always :
½ × base × perpendicular height (meaning it has to be 90° to the base), regardless of whether it is an acute, right-angled or obtuse triangle
½ × base × perpendicular height (meaning it has to be 90° to the base), regardless of whether it is an acute, right-angled or obtuse triangle
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