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primary 6 | Maths
| Data Analysis
One Answer Below
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Anyone can help me on this question . Thanks
Put 4 and 3 next to 5.
Then put 2 next to 4 and 1 next to 3.
Result :
□ 1 □
2 □□□ 3
□4□5□
5 x 4 = 20
4 x 2 = 8
3 × 1 = 3
1 × 2 = 2
Total
= 15 + 20 + 8 + 3 + 2
= 48
There are 24 unique permutations, in which there are 12 pairs which give the same product.
For example ,
□□1
2 □□ 3
□4□5□
And
□□1
3 □□ 2
□5□4□
are basically mirror images of each other.
So the logic behind my answer is :
① The largest number is 5.
I want the largest possible product from it so I will put the next two largest numbers beside it. (4 and 3)
5 × 4 + 5 × 3 is going to be bigger than any other product including 5 (i.e 5 × 2 and 5 × 1)
② Look at the next biggest number, 4.
5 is already on one side of 4 so we need to put another number on the other side of 4.
Since 3 is on the other side of 5, we can't choose 3. We have only 2 and 1 to choose from.
Choose the bigger one, 2. (Since the product 4×2 is bigger than 4×1)
③ We are left with 1 , and we put it next to 2 and 3.
Yes you can switch them around . But there are 12 different unique combinations so it's very time consuming.
The easiest way is to pair the largest numbers together for the product.
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