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primary 6 | Maths
| Data Analysis
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Hi. Anyone can explain to me how to get 6 and 1 actually ? Thank ❤
489 is the result of substituting them into the equation
There is actually a logical way to think about this :
Since we need to get 500+ on the right side, this 100b cannot be smaller than the 111a, if not we will get negative value.
So we can make a more educated guess and let b be a bigger digit than a.
What we can do first is to make 100b - 111a become close to 500
Now how much bigger should b be bigger than a?
Ideally, b should 5 larger than a, so that when we do 100b - 111a, we will get about 500.
(Since that would make the difference be close to 5 x 100. 111 is quite close to 100
Eg. If b = 9, a = 4,
9 x 100 - 4 x 100 = 500
Other possible pairings are :
b = 8, a = 3
b = 7, a = 2
b = 6, a = 1
If we let b = 7 and a = 2,
100b - 111a
= 100 x 7 - 111 x 2
= 700 - 222
= 478
Now we have 478 + d + 10c = 523
d + 10c = 523 - 478 = 45
We can distribute this 45 by letting d be and c be 4.
5 + 10 x 4 = 5 + 40 = 45
So another possible answer is : 2745
Check : 7452 - 2745 = 4707
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