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secondary 3 | A Maths
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Can't solve Q11, pls help !
Date Posted: 3 years ago
Views: 314
(5ˡᵍ²)(2ˡᵍ³)(5ˡᵍ⁹)(2ˡᵍ⁶)
= (5ˡᵍ²)(5ˡᵍ⁹)(2ˡᵍ³)(2ˡᵍ⁶)
= (5ˡᵍ²⁺ˡᵍ⁹)(2ˡᵍ³⁺ˡᵍ⁶)
= (5ˡᵍ⁽²ˣ⁹⁾)(2ˡᵍ⁽³ˣ⁶⁾)
= (5ˡᵍ¹⁸)(2ˡᵍ¹⁸)
= (5×2)ˡᵍ¹⁸
= 10ˡᵍ¹⁸
= 18
= (5ˡᵍ²)(5ˡᵍ⁹)(2ˡᵍ³)(2ˡᵍ⁶)
= (5ˡᵍ²⁺ˡᵍ⁹)(2ˡᵍ³⁺ˡᵍ⁶)
= (5ˡᵍ⁽²ˣ⁹⁾)(2ˡᵍ⁽³ˣ⁶⁾)
= (5ˡᵍ¹⁸)(2ˡᵍ¹⁸)
= (5×2)ˡᵍ¹⁸
= 10ˡᵍ¹⁸
= 18
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