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secondary 4 | E Maths
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Date Posted: 3 years ago
Views: 360
The outer surface surface is the same for both.
For the front and back surfaces, the shaded triangle in Diagram 1 is basically half the area of a square face, which is equal to the smaller shaded rectangle in Diagram 2.
For the top/bottom and side surfaces, both diagrams have a total area exposed equal to 2 square face areas.
Diagram 1 has one exposed top/bottom + 1 left/right square face for each piece.
Diagram 2 has one exposed top/bottom square face + two small rectangles (one on the left, one on the right) for each piece.
Basically, the outer surface area is the same for both. So when divided equally into two, each piece takes half the outer surface area.
The only real difference between diagram 1 and 2 is the inner surface area that's exposed after the cut.
The hypotenuse is √(2² + 2²) = √8 or 2√2
The inner surface area of the diagram 1 is greater since it's a rectangle of sides √8 cm by 2cm, but for diagram 2, it is still a 2 cm by 2 cm square.
Diagram 1 has the bigger overall exposed surface area.
For the front and back surfaces, the shaded triangle in Diagram 1 is basically half the area of a square face, which is equal to the smaller shaded rectangle in Diagram 2.
For the top/bottom and side surfaces, both diagrams have a total area exposed equal to 2 square face areas.
Diagram 1 has one exposed top/bottom + 1 left/right square face for each piece.
Diagram 2 has one exposed top/bottom square face + two small rectangles (one on the left, one on the right) for each piece.
Basically, the outer surface area is the same for both. So when divided equally into two, each piece takes half the outer surface area.
The only real difference between diagram 1 and 2 is the inner surface area that's exposed after the cut.
The hypotenuse is √(2² + 2²) = √8 or 2√2
The inner surface area of the diagram 1 is greater since it's a rectangle of sides √8 cm by 2cm, but for diagram 2, it is still a 2 cm by 2 cm square.
Diagram 1 has the bigger overall exposed surface area.
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Calculate using the 2cm sides they provide. Find C first then calculate the SA of diagram 1. Note there are only 5 faces of the cube when u cut it like that! But according to calculations as shown in the pic, diagram 1 will have a higher SA
Date Posted:
3 years ago
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