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Question
primary 6 | Maths
| Fractions
2 Answers Below
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H
YZ = 3u
Total 4u, when both have same = 2u each.
Different = 3u-1u = 2u
So, YZ give to I = 1u
1u = 63
Total they have = 4u = 4×63 = 252
When Ian have ¾ = ¾×252 = 189
Therefore, YZ must give to Ian
= 189 - 63
= 126
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