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Question
secondary 3 | E Maths
3 Answers Below
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hi i need help
Date Posted: 3 years ago
Views: 426
(x+5)×2 < 58
2x +10 < 58
2x < 48
x < 24
Therefore, largest possible x = 23.
2x +10 < 58
2x < 48
x < 24
Therefore, largest possible x = 23.
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done
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hi im not a tutor so this might be wrong, sorry in advance...but i tried so here ya go :')
Date Posted:
3 years ago
done
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hi im not a tutor so this might be wrong, sorry in advance...but i tried so here ya go :')
Date Posted:
3 years ago
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