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secondary 3 | E Maths
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Aiman
Aiman

secondary 3 chevron_right E Maths chevron_right Singapore

Pls help with part (c)...tysm

Date Posted: 3 years ago
Views: 290
AC Lim
AC Lim
3 years ago
Shortest distance, c is perpendicular to AB. Use theorem Pythagoras.
1st find distance AC use
b/sin B = a/sin A
b = a. Sin B/Sin A
b = 5.6 (Sin 100.771)/Sin 28
b = 11.718 cm

Shortest distance = 11.718 x Sin 28
Shortest distance = 5.501 ≈ 5.5 cm

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Darren Lim
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12 answers (Tutor Details)
hope this helps
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AC Lim
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12527 answers (A Helpful Person)