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primary 5 | Maths
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primary 5 chevron_right Maths chevron_right Singapore

Pls help me. I need the working urgently. Thank you in advance

Date Posted: 3 years ago
Views: 479
AC Lim
AC Lim
3 years ago
A:B:C
8:4:7 → Total = 19
After all have same sweets
= 19÷3
=19/3

B received = 19/3 - 4 = 7/3
Therefore,
7/3 → 14
1/3 → 2

A left 19/3 after give to B
Therefore, total give to B
= 8-19/3
= 5/3
= 5/3 × 2 ÷ 1/3
= 10 sweets.

Total = 19
1/3→2
19 = 19×2÷1/3 = 114
Total sweets = 114
Anvita
Anvita
3 years ago
Thank you

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