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Secondary 1 | Maths
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Answer 2⁴ × 3 × 11 (528), 2⁴ × 3 × 7 (336), 3⁵ (243), etc. Please help, I don’t understand the question.
2 × 2 × 2 × 2 × 3 × 3 × 3 × 3 × 3 × 7 × 7 × 11
Now these are all the copies of the prime factors this number has.
Any factor of this number can have a mixture of copies of these prime factors.
Recall that prime factors are the simplest and cannot be broken down anymore.
So just pick some prime factors from the above , such that you get a product which is above 100.
2⁴ × 3⁵ × 7² × 11
If I were to pick two 7s and two 2 s, I can rewrite it as :
(2² × 3⁵ × 11) × 2² × 7²
= (2² × 3⁵ × 11) × 4 × 49
= (2² × 3⁵ × 11) × 196
So my factor is 196 and the number is a multiple of 196 and (2² × 3⁵ × 11)
The important thing is to know what the index notation stands for.
① aⁿ = a × a × a × a .... (there are n copies of a)
Eg.
2⁴ = 2 × 2 × 2 × 2 (4 copies of 2)
② aⁿ⁺ᵐ = aⁿ × aᵐ
Eg.
2⁴
= 2³⁺¹
= 2³ × 2¹
= (2 × 2 × 2) × (2)
= 2 × 2 × 2 × 2
③ aⁿ⁻ᵐ = aⁿ ÷ aᵐ = aⁿ/aᵐ
Eg.
3⁵
= 3⁷⁻²
= 3⁷/3²
= (3×3×3×3×3×3×3)/(3×3)
= 3×3×3×3×3
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