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junior college 2 | H2 Maths
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Date Posted: 3 years ago
Views: 419
Because,
√(-3 + 4i)
= √(1 + 4i - 4)
= √(1 + 2(1)(2i) + 4(-1))
= √(1 + 2(1)(2i) + 4i²)
= √(1 + 2(1)(2i) + (2i)²)
(Notice that this is in the form a² + 2ab + b² , so we can rewrite it as (a + b)² somce they are equal)
= √(1 + 2i)²
= 1 + 2i
√(-3 + 4i)
= √(1 + 4i - 4)
= √(1 + 2(1)(2i) + 4(-1))
= √(1 + 2(1)(2i) + 4i²)
= √(1 + 2(1)(2i) + (2i)²)
(Notice that this is in the form a² + 2ab + b² , so we can rewrite it as (a + b)² somce they are equal)
= √(1 + 2i)²
= 1 + 2i
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