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junior college 2 | H2 Maths
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Please help with hence, thank you
Date Posted: 3 years ago
Views: 264
You have to rewrite the denominator on the left in the form similar to the first part.
Since the first part is 2x, we need to rewrite it as 2 'something'
2ˣ⁺¹ + 2
= 2(2ˣ) + 2
= 2(2ˣ + 1)
The term on the right hand side undergoes the same change.
2ˣ - 1
= 2ˣ - 1 + 1 - 1
= (2ˣ + 1) - 2
This is in the form 'something' - 2
So, simply substitute x from the first part with 2ˣ + 1
Since the first part is 2x, we need to rewrite it as 2 'something'
2ˣ⁺¹ + 2
= 2(2ˣ) + 2
= 2(2ˣ + 1)
The term on the right hand side undergoes the same change.
2ˣ - 1
= 2ˣ - 1 + 1 - 1
= (2ˣ + 1) - 2
This is in the form 'something' - 2
So, simply substitute x from the first part with 2ˣ + 1
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