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primary 6 | Maths
| Fractions
4 Answers Below
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May I hv the working?
Date Posted: 3 years ago
Views: 515
Alan and Mike have $800 altogether.
Let Mike's money be ⬛⬛⬛⬛⬛
1/5 of that = ⬛
Since ¼ of Alan's money is $65 more than 1/5 of Mike's,
¼ of Alan's money = ⬛ + $65
Alan's money in total = 4 times of (⬛ + $65)
= ⬛⬛⬛⬛ + 4 x $65
= ⬛⬛⬛⬛ + $260
Total they have = ⬛⬛⬛⬛⬛ + ⬛⬛⬛⬛ + $260
= ⬛⬛⬛⬛⬛⬛⬛⬛⬛ + $260
This equals $800
Let Mike's money be ⬛⬛⬛⬛⬛
1/5 of that = ⬛
Since ¼ of Alan's money is $65 more than 1/5 of Mike's,
¼ of Alan's money = ⬛ + $65
Alan's money in total = 4 times of (⬛ + $65)
= ⬛⬛⬛⬛ + 4 x $65
= ⬛⬛⬛⬛ + $260
Total they have = ⬛⬛⬛⬛⬛ + ⬛⬛⬛⬛ + $260
= ⬛⬛⬛⬛⬛⬛⬛⬛⬛ + $260
This equals $800
So,
⬛⬛⬛⬛⬛⬛⬛⬛⬛ = $800 - $260 = $540
⬛ = $540 ÷ 9 = $60
Difference between Alan and Mike
= ⬛⬛⬛⬛ + $260 - ⬛⬛⬛⬛⬛
= $260 - ⬛
= $260 - $60
= $200
Alan has $200 more than Mike.
⬛⬛⬛⬛⬛⬛⬛⬛⬛ = $800 - $260 = $540
⬛ = $540 ÷ 9 = $60
Difference between Alan and Mike
= ⬛⬛⬛⬛ + $260 - ⬛⬛⬛⬛⬛
= $260 - ⬛
= $260 - $60
= $200
Alan has $200 more than Mike.
Thks for yr help!
See 4 Answers
Thanks for yr help!
This method uses simultaneous equation. See my other method below
Ok. Thks!
Can't understand. Can use model? Thks!
Thks!
Thks for yr help!
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