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primary 6 | Maths
| Geometry
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These triangles have height and base both equal to the radius of the circle.
Area of each right angled triangle
= 98 cm² ÷ 4
= 24.5 cm²
But area of each right angled triangle also
= ½ x base x height
= ½ radius of circle x radius of circle
So,
½ radius of circle x radius of circle = 24.5 cm²
radius of circle x radius of circle = 24.5 cm² x 2 = 49cm²
(This is the same as two triangles combined to form a square with sides equal in length to the radius.)
Radius of circle = √49 cm = 7cm
(Or realise that 7 x 7 = 49 so the radius must be 7cm)
Circumference of circle (2πr)
= 2 x 22/7 cm x 7 cm
= 44 cm
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