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primary 6 | Maths
| Algebra
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Please help me with these questions. These are from a Math Olympiad paper. Thank you!
Date Posted: 3 years ago
Views: 486
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I+S+T = ¼ big circle
= ¼ ×(22/7)×28² = 616
I+T = ¼ big circle - ¼ small circle
= ¾ × 616 = 462
II + T = rectangle
= 14×28 = 392
I - II = 462-392 = 70cm²(Ans)
= ¼ ×(22/7)×28² = 616
I+T = ¼ big circle - ¼ small circle
= ¾ × 616 = 462
II + T = rectangle
= 14×28 = 392
I - II = 462-392 = 70cm²(Ans)
Date Posted:
3 years ago
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