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secondary 4 | A Maths
4 Answers Below
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need help with the ticked questions only (qn 1,5,7,9,13,14, 17,18), pls explain too
Date Posted: 3 years ago
Views: 193
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Q1, Q5, Q7a
All the techniques which you have learnt previously in algebraic differentiation will continue to be applied here.
All the techniques which you have learnt previously in algebraic differentiation will continue to be applied here.
Date Posted:
3 years ago
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Q7b, Q9
Date Posted:
3 years ago
The rest another time
thx :) sorry, can you help me with qn14, 18 and 22 too
There is no Q22 in the photo
sorry i have just posted it
for 7b, when i type ln(1/e)^2 into the calculator, i get 1 instead of - 2 tho
There is a difference between
ln (1/e)^2
and
[ln (1/e)]^2.
The first one will give you a value of -2
The second one will give you a value of 1
ln (1/e)^2
and
[ln (1/e)]^2.
The first one will give you a value of -2
The second one will give you a value of 1
Wait, my answer there wrong, it’s 1/e times (-2), I went to put it as 1/e minus 2 which has an entirely different meaning
Correct coordinate for Q7b is (1/e, -2/e)
i typed ln(1/e)^2 without brackets surrounding the whole function but i still got 1.....
i tried typing ln(1/e^2) now and i got - 2, but the brackets are originally at (1/e)^2 according to y although both are actually the same
i tried typing ln(1/e^2) now and i got - 2, but the brackets are originally at (1/e)^2 according to y although both are actually the same
The original expression has the square only on the 1/e.
In the calculator, we bracket the (1/e) before squaring it.
Press in the calculator.
Then take ln of this value.
In the calculator, we bracket the (1/e) before squaring it.
Press in the calculator.
Then take ln of this value.
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Q18
Date Posted:
3 years ago
we can automatically cancel out 2e^x^2+3x from the entire equation as it does not satisfy the requirement of y<0?
“2” and “e^anything” can be ignored since these are positive and will make no contribution to the signage of the expression.
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Q13, Q17
Date Posted:
3 years ago
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