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secondary 4 | A Maths
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need help with these qns, pls explain too
Next two days I am not available at all
also need explanation as i dont really know how exponential and logarithmic differentiation works... especially the questions at my most recent post on differentiation of exponential functions as im unable to do it
sin x ==> cos x
cos x ==> - sin x
tan x ==> sec² x
e^x ==> e^x (remains unchanged!)
ln x ==> 1/x (one of the unusual ones in which a logarithm suddenly becomes purely algebraic)
For the chain rules to apply, there are rules to follow also.
The chain rule for trigonometric terms applies in the angle mentioned. For example, in sin 2x, the angle is 2x, so the chain rule requires us to differentiate the 2x. Similarly, in tan (2x² + 3x), the angle is (2x² + 3x), so we must differentiate this.
sin 2x ==> 2 cos 2x
tan (2x² + 3x) ==> (4x + 3) sec² (2x² + 3x)
The chain rule for exponential terms applies in the power of the exponential, while the chain rule for logarithmic terms applies in the terms to be logged.
d/dx (ln 4) is zero and not 1/4 since there is no x in it (i.e. d/dx (ln x) is 1/x but the same cannot be said for d/dx (ln 4))
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for question 3, why is it not 3ln(ex+6) using the power rule tho