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secondary 3 | A Maths
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pls help, need it asap for part b
Date Posted: 3 years ago
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(27√3 + 34√2) / (11 + 4√6)
= (27√3 + 34√2) / (11 + 4√6) × (11 - 4√6) / (11 - 4√6)
= (27√3 + 34√2)(11 - 4√6) / (11² - (4(√6))²)
= (297√3 - 108√3√6 + 374√2 - 136√2√6) / (121 - 96)
= (297√3 - 108√3√3√2 + 374√2 - 136√2√2√3) / 25
= (297√3 - 324√2 + 374√2 - 272√3) / 25
= (25√3 + 50√2) / 25
= √3 + 2√2
The height of this cuboid is equal in length to the sides of its square base. Since all 3 dimensions (the length, width and height) are the same, it is actually a cube.
= (27√3 + 34√2) / (11 + 4√6) × (11 - 4√6) / (11 - 4√6)
= (27√3 + 34√2)(11 - 4√6) / (11² - (4(√6))²)
= (297√3 - 108√3√6 + 374√2 - 136√2√6) / (121 - 96)
= (297√3 - 108√3√3√2 + 374√2 - 136√2√2√3) / 25
= (297√3 - 324√2 + 374√2 - 272√3) / 25
= (25√3 + 50√2) / 25
= √3 + 2√2
The height of this cuboid is equal in length to the sides of its square base. Since all 3 dimensions (the length, width and height) are the same, it is actually a cube.
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