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Question
primary 6 | Maths
| Measurement
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10q
Date Posted: 3 years ago
Views: 277
At 1st Apple = 120
Pear = 80
Pear = 80
In the end
Mike A:P = 4:1
Apple =4u
Pear =1u ❴50%-25❵
Jack A:P 2:1
Apple = 4u+20
Pear = 1u +25
4u+20 = 2 × (1u+25)
4u+20 = 2u+50
4u-2u= 50-20
2u = 30
u=15
Pear Jack have 1u+25
= 15+25
=40
Therefore total pear Jack bought = 2×40 =80
Hope this helps
Mike A:P = 4:1
Apple =4u
Pear =1u ❴50%-25❵
Jack A:P 2:1
Apple = 4u+20
Pear = 1u +25
4u+20 = 2 × (1u+25)
4u+20 = 2u+50
4u-2u= 50-20
2u = 30
u=15
Pear Jack have 1u+25
= 15+25
=40
Therefore total pear Jack bought = 2×40 =80
Hope this helps
See 1 Answer
In the end
Mike A:P = 4:1
Apple =4u
Pear =1u ❴50%-25❵
Jack A:P 2:1
Apple = 4u+20
Pear = 1u +25
4u+20 = 2 × (1u+25)
4u+20 = 2u+50
4u-2u= 50-20
2u = 30
u=15
Pear Jack have 1u+25
= 15+25
=40
Therefore total pear Jack bought = 2×40 =80
Hope this helps
Mike A:P = 4:1
Apple =4u
Pear =1u ❴50%-25❵
Jack A:P 2:1
Apple = 4u+20
Pear = 1u +25
4u+20 = 2 × (1u+25)
4u+20 = 2u+50
4u-2u= 50-20
2u = 30
u=15
Pear Jack have 1u+25
= 15+25
=40
Therefore total pear Jack bought = 2×40 =80
Hope this helps
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