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junior college 1 | H2 Maths
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need help with the circled part
Date Posted: 3 years ago
Views: 223
hint ...
since P lies on OB then vector OP = k(vector OB) where k is a constant.
vector AP = AO + OP
when 2 vectors are perpendicular, dot product is zero.
put AP dot OB equal zero and solve for k, then use k to get OP.
final answer for your reference ...
OP = 2i -(8/5)j+(6/5)k
since P lies on OB then vector OP = k(vector OB) where k is a constant.
vector AP = AO + OP
when 2 vectors are perpendicular, dot product is zero.
put AP dot OB equal zero and solve for k, then use k to get OP.
final answer for your reference ...
OP = 2i -(8/5)j+(6/5)k
thanks so much!! managed to understand the question better and solved it already!! :))
See 1 Answer
thanks
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